SOLUTION: Use the Laws of Logarithms to expand the expression: {{{ log(base 5) (x/2) }}} {{{ log(base 6) cuberoot of x^2 + 7 }}} {{{ log(base 8)(xy)^7}}} sorry if it comes of

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Use the Laws of Logarithms to expand the expression: {{{ log(base 5) (x/2) }}} {{{ log(base 6) cuberoot of x^2 + 7 }}} {{{ log(base 8)(xy)^7}}} sorry if it comes of      Log On


   

Question 914023: Use the Laws of Logarithms to expand the expression:
+log%28base+5%29+%28x%2F2%29+

+log%28base+6%29+cuberoot+of+x%5E2+%2B+7+

+log%28base+8%29%28xy%29%5E7
sorry if it comes off confusing I just didn't know how to write those out


Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
log(base 5) (x/2)

log(base 6) cuberoot of x^2 + 7

log(base 8)(xy)^7

"sorry if it comes off confusing I just didn't know how to write those out"

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You ask about expanding each expression.

log(base 5) (x/2)
Text for algebra.com: log(5,(x/2))
rendering tags: log%285%2C%28x%2F2%29%29
-
highlight%28log%285%2Cx%29-log%285%2C2%29%29

log(base 6) cuberoot of x^2 + 7
You probably meant this:
Text for algebra.com: log(6,(root(3,(x^2+7))))
rendering tags: log%286%2C%28root%283%2C%28x%5E2%2B7%29%29%29%29
-
The cubed root means "to the one-third power".
highlight%28%281%2F3%29log%286%2C%28x%5E2%2B7%29%29%29
No way in Real numbers to split the argument expression any further.

log(base 8)(xy)^7
Text for algebra.com: log(8,((xy)^7))
rendering tags: log%288%2C%28%28xy%29%5E7%29%29
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7%2Alog%288%2C%28%28xy%29%29%29
highlight%287%2Alog%288%2Cx%29%2B7%2Alog%288%2Cy%29%29