SOLUTION: Two planes start from the same airport at the same time. One plane heads North at a speed 50 miles faster than the other plane that heads East. After 3 hours they are 2440 miles ap

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Question 914015: Two planes start from the same airport at the same time. One plane heads North at a speed 50 miles faster than the other plane that heads East. After 3 hours they are 2440 miles apart. What is the speed of each plane?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
Weird one
let east bound plane speed =x
north bound plane speed = (x+50)
After 3 hours they have flown at right angles to each othe a distance of 3x &
3(x+50) miles
At any given time they form a right triangle with the origin
(3(x))^2+(3(x+50))^2 = (2440)^2
/9
(x))^2+(x+50)^2 = (2440)^2/9
x^2+x^2+100x+2500= 661511.11
2x^2+100x-659011.11=0
solve by formula method
to get the value of x
Find the roots of the equation by quadratic formula

a= 2 ,b= 100 ,c= -659011.11

b^2-4ac= 10000 - -5272088.89
b^2-4ac= 5282088.89
x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-12%2B21%29%2F%2812%29
x1=( 2198.28 )/ 4
x1= 549.57 ft
x2=( -100 -2298.28 ) / 4
x2= -599.57
Ignore negative value
Round off
x= 550 plane I
600 = plane II