SOLUTION: solve the equation show all work x^2 - 3x = 10 x^2 - 3x + 10 = 0 x(x-3 + 10) = 0 I have no idea how to finish this problem

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Question 91368This question is from textbook algebra and trigonometry
: solve the equation show all work
x^2 - 3x = 10
x^2 - 3x + 10 = 0
x(x-3 + 10) = 0
I have no idea how to finish this problem
This question is from textbook algebra and trigonometry

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+-+3x+=+10

x%5E2+-+3x+-+10=0 Subtract (not add) 10 from both sides. This is where you make a mistake


%28x-5%29%28x%2B2%29=0 Factor the left side (note: if you need help with factoring, check out this solver)



Now set each factor equal to zero:

x-5=0 or x%2B2=0

x=5 or x=-2 Now solve for x in each case


So our solutions are x=5 or x=-2


Notice if we graph y=x%5E2-3x-10 we get

+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C+x%5E2-3x-10%29+

and we can see that the graph has roots at x=5 and x=-2, so this verifies our answer.