SOLUTION: find 3 consecutive even integers such that the sum of 1st and 3rd is 192.

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Question 913473: find 3 consecutive even integers such that the sum of 1st and 3rd is 192.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
x = first integer
x+2 = second consecutive even integer
x+4 = third consecutive even integer

"the sum of 1st and 3rd is 192." ----> %28x%29%2B%28x%2B4%29+=+192


%28x%29%2B%28x%2B4%29+=+192

x%2Bx%2B4+=+192

2x%2B4+=+192

2x+=+192-4

2x+=+188

x+=+188%2F2

x+=+94

The first integer is x+=+94.

The second integer is x%2B2=94%2B2=96

The third integer is x%2B4=94%2B4=98

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Final Answer: The three integers are 94, 96, 98


Let me know if you need more help or if you need me to explain a step in more detail.
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Thanks,

Jim