Question 913348: An April 2004 article on Hear The Issues.com stated that Americans have an average of 2.24 televisions per household (source: Nielsen Media Research). If the standard deviation for the number of televisions in a U.S. household is 1.2 and a random sample of 80 American households is selected, the mean of this sample belongs to a sampling distribution.
- What is the mean and standard deviation of this sampling distribution?
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Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! standard deviation of sampling distribution(sigma(x)) = standard deviation / sqrt(n), where n is the sample size, then
sigma(x) = 1.2 / sqrt(80) = 0.134164079
The mean of the population is equal to the sampling distribution mean (mean(x)) since n >= 30,
mean(x) = 2.24
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