SOLUTION: How would I solve this natural logarithm? ln(e^-20 ln e) And this regular logarithm log(7/2) Thank you

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Question 913344: How would I solve this natural logarithm?
ln(e^-20 ln e)
And this regular logarithm
log(7/2)
Thank you
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

ln%28e%5E-20%2A+ln+%28e%29+%29
= ln%28e%5E-20%29%2Bln%28+ln+%28e%29+%29
= ln%28e%5E-20%29%2Bln%28+ln+%28e%29+%29 ............. ln%28e%5E-20%29=-20 and ln%28+ln+%28e%29+%29=0
so, ln%28e%5E-20+%2Aln+e%29+=-20

log%287%2F2%29=log%287%29-log%282%29=0.84509-0.3010299=0.54406