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Question 913223: Find 3consecutive integers so that twice the first added to five times the second exceeds three times the third by 51.
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! Find 3consecutive integers so that twice the first added to five times the second exceeds three times the third by 51.
3consecutive integers be x, x+1 & x+2
so that twice the first= 2x
added to five times the second =5(x+1)
exceeds three times the third =3(x+2)
by 51.
2x+5(x+1)=3(x+2) +51
2x+5x+5=3x+6+51
4x=52
x= 13
13,14,15
=
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