Question 913201: The probability that a pen drawn at random from a box of pen is defective is 0.1. If a sample of 6 pens is taken, the probability of
1) no defective pens
2) 5 or 6 defective pens
3) Less than 3 defective pens
Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! p = .1, n = 6
1) P(x = 0) = binompdf(6, .1, 0) 0r (.9)^6
2) P(x = 5 or 6 defective pens) = binompdf(6, .1, 5) + binompdf(6, .1, 6)
3) P(Less than 3 defective pens) = binomcdf(6, .1, 2)
..........
Or by hand Using
p and q are the probabilities of success and failure respectively.
In this case p = .1 & q = .9 , n = 6
............For ex
3) P(Less than 3 defective pens) = P(0) + P(1)+ P(2)
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