You can put this solution on YOUR website! Given that log2=0.3010,log3=0.4771 and log7=0.8451.evaluate (a)log5 (b)log49 (c)log14
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(a) log(5)=log(10/2)=log(10)-log(2)=1-log(2)=1-.3010=.6990
(b) log(49)=log(7^2)=2log(7)=2*0.8451=1.6902
(c) log(14)=log(2*7)=log(2)+log(7)=0.3010+0.8451=1.1461