SOLUTION: Train A leaves a station at 8:00 and travels at 100 km per hour towards the next city. One and a half hours later, Train B, an express, leaves the same station, traveling at 160 km
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-> SOLUTION: Train A leaves a station at 8:00 and travels at 100 km per hour towards the next city. One and a half hours later, Train B, an express, leaves the same station, traveling at 160 km
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Question 912941: Train A leaves a station at 8:00 and travels at 100 km per hour towards the next city. One and a half hours later, Train B, an express, leaves the same station, traveling at 160 km per hour along the same route. At what time will Train B overtake the slower train? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! First find train A's head start km
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Start a stopwatch when train B leaves
Let = the time in hours it takes
for B to catch A
Let = the distance that B travels
until it catches A
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Train A's equation:
(1)
Train B's equation:
(2)
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Substitute (2) into (1)
(1)
(1)
(1)
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8:00 + = 12:00
Train B catches train A at 12:00
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check:
(2)
(2)
(2)
and
(1)
(1)
(1)
(1)
OK
