SOLUTION: A jar contains $18.50 in dimes and quarters. There are 110 coins in the jar. Find the number of each kind of coin.

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Question 912562: A jar contains $18.50 in dimes and quarters. There are 110 coins in the jar. Find the number of each kind of coin.
Found 2 solutions by Edwin McCravy, ewatrrr:
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
system%2810d+%2B+25q+=+1850%2C%0D%0A++d+%2B+q+=+110%29
Solve that by substitution and get 60 dimes and 50 quarters.

60 dimes    = 60 times $0.10 = $ 6.00
50 quarters = 50 times $0.25 = $12.50
-------------------------------------
                       Total = $18.50

Edwin

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x the number of quarters
CENTS makes sense
25x + 10(110-x) = 1850
15x = 750
x = 50, number of quarters. Dimes 60 110-50
and...checking
1250 +600 = 1850 0r $18.50