SOLUTION: Find the center radius form of 4x^2+4x+4y^2+32y-79=0

Algebra ->  College  -> Linear Algebra -> SOLUTION: Find the center radius form of 4x^2+4x+4y^2+32y-79=0       Log On


   

Question 912501: Find the center radius form of 4x^2+4x+4y^2+32y-79=0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
4x%5E2%2B4x%2B4y%5E2%2B32y-79=0
x%5E2%2Bx%2By%5E2%2B8y-79%2F4=0
Complete the square in x and y
%28x%5E2%2Bx%2B1%2F4%29%2B%28y%5E2%2B8y%2B16%29-79%2F4=1%2F4%2B16
%28x%2B1%2F2%29%5E2%2B%28y%2B4%29%5E2=1%2F4%2B64%2F4%2B79%2F4
%28x%2B1%2F2%29%5E2%2B%28y%2B4%29%5E2=144%2F4
highlight%28%28x%2B1%2F2%29%5E2%2B%28y%2B4%29%5E2=36%29
.
.
.
Center : (-1/2,-4)
Radius : 6