SOLUTION: Find the horizontal asymptote of F(x) =5x^2+1/ x^2+2x+1

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Question 91245: Find the horizontal asymptote of F(x) =5x^2+1/ x^2+2x+1
Answer by mathispowerful(115) About Me  (Show Source):
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Find the horizontal asymptote of F(x) =5x^2+1/ x^2+2x+1
horizontal asymptote is the F(x) value when x is very large.
in %285x%5E2%2B1%29%2F%28+x%5E2%2B2x%2B1%29
when x becomes very large constant terms and x terms are relatively small compared to x%5E2 terms, so F(x) value is determined by x%5E2 terms, that is
%285x%5E2%29%2F%28x%5E2%29
which gives us 5.
So the answer to your question is horizontal asymptote is y = 5
see graph below
graph%28400%2C200%2C-30%2C30%2C-2%2C7%2C+%285x%5E2%2B1%29%2F%28+x%5E2%2B2x%2B1%29%29
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