SOLUTION: A bag contains 10 counters, of which 7 are green and 3 are while. A counter is picked at random from the bag and its color is noted. The counter is not replaced. A second counte
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-> SOLUTION: A bag contains 10 counters, of which 7 are green and 3 are while. A counter is picked at random from the bag and its color is noted. The counter is not replaced. A second counte
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Question 912410: A bag contains 10 counters, of which 7 are green and 3 are while. A counter is picked at random from the bag and its color is noted. The counter is not replaced. A second counter is then picked. Find the probability that
a) the first counter is green
b) the first counter is and green and the second is white
c) the counters are different colors Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A bag contains 10 counters, of which 7 are green and 3 are while. A counter is picked at random from the bag and its color is noted. The counter is not replaced. A second counter is then picked. Find the probability that
a) the first counter is green:: 7/10
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b) the first counter is green and the second is white::(7/10)(3/9)= 7/30
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c) the counters are different colors
P(both are green) = 7C2/10C2
P(both are white) = 3C2/10C2
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Ans: P(diffferent colors) = 1-[7C2+3C2]/10C2 = 1 - [24/45] = 21/45 = 7/15
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Cheers,
Stan H.
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