SOLUTION: solve (x+4)^2=25

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Question 91239: solve (x+4)^2=25
Answer by praseenakos@yahoo.com(507) About Me  (Show Source):
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Question:

solve (x+4)^2=25

Answer:

%28x%2B4%29%5E2+=+25+

Take square root on both sides...


==> sqrt%28x+%2B+4%29%5E2+=+sqrt%2825%29+


==> x + 4 = 5 or -5

Suppose x + 4 = 5

Subtract 4 from both sides of the expression

==> x + 4 - 4 = 5 - 4

==> x = 1


Suppose x + 4 = -5

Subtract 4 from both sides of the expression

==> x + 4 - 4 = -5 - 4

==> x = -9

So we have two values of x

Hence the solution is ,
x = 1 and x= -9


Hope you found the explanation useful.

Regards.
praseena.