SOLUTION: A recent report in BusinessWeek indicated that 20 percent of all employees steal from their company each year. (Round z-score computation to 2 decimal places and your final answer

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Question 912324: A recent report in BusinessWeek indicated that 20 percent of all employees steal from their company each year. (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)

If a company employs 50 people, what is the probability that:

(a) Fewer than 5 employees steal?

(b) More than 5 employees steal?

(c) Exactly 5 employees steal?

(d) More than 5 but fewer than 15 employees steal?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
p = .20
a) Use 4.5, 4.5/50 = .09
P(x < 5), z = +%28.09-.2%29%2Fsqrt%28.2%2A.8%2F50%29+=+-.11%2F.057+=+++-1.93 P(z < -1.93) = .0268 0r 2.68%
b) Use 5.5, 5.5/50 = .11
P(x > 5), z = +%28.11-.2%29%2Fsqrt%28.2%2A.8%2F50%29+=+-.09%2F.057+=+++-1.58 P(z < -1.58) = .0571 0r 5.71%
c) P(x = 5) = .0571 - .0268
d)
P(x < 15) = 14.5/50, P(z < (.29-.20)/.057))= P(z < .09/.057) = P(z < 1.58) = .9428
P(5 < x < 15) = .9428 - .0268