SOLUTION: Please help explain what I need to do with this problem: 9^x= 4sqrt3

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Please help explain what I need to do with this problem: 9^x= 4sqrt3      Log On


   

Question 91224: Please help explain what I need to do with this problem:
9^x= 4sqrt3
Answer by vertciel(183) About Me  (Show Source):
You can put this solution on YOUR website!
Hello there,
We'll need to use logarithm to solve for x.
9^x = 4√3
ln 9^x = ln 4√3
x ln 9 = ln 4√3
x = (ln 4√3)/(ln 9)
x ≈ 0.88093
Check: 9^0.88093 ≈ 6.928207