You can put this solution on YOUR website! If f(x)=2x^2+3x-4 than f(3-x) can be written in the form ax^2+bx+c where a,b,c are integers. Find a+b+c.
***
f(x)=2x^2+3x-4
f(3-x)=2(3-x)^2+3(3-x)-4
=2(9-6x+x^2)+9-3x-4
=18-12x+2x^2+9-3x-4
=2x^2-15x+23
a=2
b=-15
c=23