SOLUTION: hello, i'm not sure if this question even belongs in this area but if you could please help me that would be so great!! I've tried it like a 10 different ways and cannot come up wi

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: hello, i'm not sure if this question even belongs in this area but if you could please help me that would be so great!! I've tried it like a 10 different ways and cannot come up wi      Log On


   

Question 912136: hello, i'm not sure if this question even belongs in this area but if you could please help me that would be so great!! I've tried it like a 10 different ways and cannot come up with the right answer.
here it is:
((x+1)/(x-1))=((-7x)/(x+3))+((8)/(x-1)(x+3))
If you could help me that would be the best.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2B1%29%2F%28x-1%29=%28-7x%29%2F%28x%2B3%29%2B%288%29%2F%28x-1%29%28x%2B3%29
Use (x-1)*(x+3) as the commmon denominator

Since the DEN's are equal:
%28x%2B1%29%2A%28x%2B3%29+=+%28-7x%29%2A%28x-1%29+%2B+8
x%5E2+%2B+4x+%2B+3+=+-7x%5E2+%2B+7x+%2B+8
8x%5E2+-+3x+-+5+=+0
(x - 1)*(8x + 5) = 0
x = 1 --- reject, makes the DEN zero
x = -5/8