SOLUTION: determine the solution sets of the following systems of linear equation by elimination. 6x+2y=-10 -5x-3y=11

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Question 911970: determine the solution sets of the following systems of linear equation by elimination.

6x+2y=-10
-5x-3y=11

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

6%2Ax%2B2%2Ay=-10
-5%2Ax-3%2Ay=11

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 6 and -5 to some equal number, we could try to get them to the LCM.

Since the LCM of 6 and -5 is -30, we need to multiply both sides of the top equation by -5 and multiply both sides of the bottom equation by -6 like this:

-5%2A%286%2Ax%2B2%2Ay%29=%28-10%29%2A-5 Multiply the top equation (both sides) by -5
-6%2A%28-5%2Ax-3%2Ay%29=%2811%29%2A-6 Multiply the bottom equation (both sides) by -6


So after multiplying we get this:
-30%2Ax-10%2Ay=50
30%2Ax%2B18%2Ay=-66

Notice how -30 and 30 add to zero (ie -30%2B30=0)


Now add the equations together. In order to add 2 equations, group like terms and combine them
%28-30%2Ax%2B30%2Ax%29-10%2Ay%2B18%2Ay%29=50-66

%28-30%2B30%29%2Ax-10%2B18%29y=50-66

cross%28-30%2B30%29%2Ax%2B%28-10%2B18%29%2Ay=50-66 Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.



So after adding and canceling out the x terms we're left with:

8%2Ay=-16

y=-16%2F8 Divide both sides by 8 to solve for y



y=-2 Reduce


Now plug this answer into the top equation 6%2Ax%2B2%2Ay=-10 to solve for x

6%2Ax%2B2%28-2%29=-10 Plug in y=-2


6%2Ax-4=-10 Multiply



6%2Ax=-10%2B4 Subtract -4 from both sides

6%2Ax=-6 Combine the terms on the right side

cross%28%281%2F6%29%286%29%29%2Ax=%28-6%29%281%2F6%29 Multiply both sides by 1%2F6. This will cancel out 6 on the left side.


x=-1 Multiply the terms on the right side


So our answer is

x=-1, y=-2

which also looks like

(-1, -2)

Notice if we graph the equations (if you need help with graphing, check out this solver)

6%2Ax%2B2%2Ay=-10
-5%2Ax-3%2Ay=11

we get



graph of 6%2Ax%2B2%2Ay=-10 (red) -5%2Ax-3%2Ay=11 (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).


and we can see that the two equations intersect at (-1,-2). This verifies our answer.