SOLUTION: A particle moves on a vertical line so that it's coordinate in feet at time (t) is s(t) = 4t^3 - 12t^2 +7 , t >= 0
a)
Find the Velocity function
b)
Find the Accelerati
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-> SOLUTION: A particle moves on a vertical line so that it's coordinate in feet at time (t) is s(t) = 4t^3 - 12t^2 +7 , t >= 0
a)
Find the Velocity function
b)
Find the Accelerati
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Question 911969: A particle moves on a vertical line so that it's coordinate in feet at time (t) is s(t) = 4t^3 - 12t^2 +7 , t >= 0
a)
Find the Velocity function
b)
Find the Acceleration function
c)
When is the particle moving upward?
d)
When is the particle moving downward?
e)
What is the total distance that the particle travels in the time interval 0 <= t <= 3
You can put this solution on YOUR website! A particle moves on a vertical line so that it's coordinate in feet at time (t) is s(t) = 4t^3 - 12t^2 +7 , t >= 0
a)
Find the Velocity function
b)
Find the Acceleration function
c)
When is the particle moving upward?
d)
When is the particle moving downward?
e)
What is the total distance that the particle travels in the time interval 0 <= t <= 3
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a)
Find the Velocity function
Differentiate the position function s(t) to get v(t) = s'(t) the velocity function
s(t) = 4t^3 - 12t^2 +7
s'(t) = 3*4t^2 - 2*12t^1 +0
s'(t) = 12t^2 - 24t
v(t) = 12t^2 - 24t
The velocity function is v(t) = 12t^2 - 24t
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b)
Find the Acceleration function
Differentiate the velocity function v(t) to get the acceleration function a(t) = v'(t). This is equivalent to finding the second derivative of s(t)
v(t) = 12t^2 - 24t
v'(t) = 2*12t^1 - 1*24t^0
v'(t) = 24t - 24*1
v'(t) = 24t - 24
a(t) = 24t - 24
The acceleration function is a(t) = 24t - 24
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c)
When is the particle moving upward?
The particle moves upward when v(t) > 0, essentially when the velocity is positive.
Graph v(t) = 12t^2 - 24t to get
We see that the velocity function is positive when or . The inequality does not make sense in this case because negative time is not possible. So only focus on
The particle is moving upward when (beyond 2 seconds)
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d)
When is the particle moving downward?
Use the same graph in part c) to find that the velocity is negative when . This is when the particle is moving downward.
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e)
What is the total distance that the particle travels in the time interval 0 <= t <= 3
D = total distance the particle travels in the time interval 0 <= t <= 3
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