SOLUTION: A particle moves on a vertical line so that it's coordinate in feet at time t is s(t) = 4t^3 - 12t^2 + 7 , t ≥ 0
a)
Find the velocity and acceleration functions.
b)
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a)
Find the velocity and acceleration functions.
b)
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Question 911874: A particle moves on a vertical line so that it's coordinate in feet at time t is s(t) = 4t^3 - 12t^2 + 7 , t ≥ 0
a)
Find the velocity and acceleration functions.
b)
When is the particle moving upward and when is it moving downward?
c
Find the total distance that the particle travels in the time interval 0 ≤ t ≤ 3
You can put this solution on YOUR website! A particle moves on a vertical line so that it's coordinate in feet at time t is s(t) = 4t^3 - 12t^2 + 7 , t >= 0
a)
Find the velocity and acceleration functions.
s(t) = 4t^3 - 12t^2 + 7
Velocity is s' = 12t^2 - 24t
Accel is s" = 24t - 24
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b)
When is the particle moving upward and when is it moving downward?
Vel + --> up
12t^ - 24t > 0
Solve 12t^2 - 24t = 0 --> Vel + for t > 2
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Vel - --> down
12t^ - 24t < 0
0 <= t <= 2
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c
Find the total distance that the particle travels in the time interval 0 <= t <= 3
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Distance = 32.292929...
I'll do that later.
