SOLUTION: Mrs. Whinship sells chocolate fudge for 7.50 per pound and peanut butter fudge for 7.00 per pound. The total number of pounds sold on Saturday was 146 and the total amount of money

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Mrs. Whinship sells chocolate fudge for 7.50 per pound and peanut butter fudge for 7.00 per pound. The total number of pounds sold on Saturday was 146 and the total amount of money      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 911741: Mrs. Whinship sells chocolate fudge for 7.50 per pound and peanut butter fudge for 7.00 per pound. The total number of pounds sold on Saturday was 146 and the total amount of money collected was 1065.00. How many pounds of each type of fudge were sold?
Found 2 solutions by josmiceli, richwmiller:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = pounds of c.f. sold
Let +b+ = pounds of p.b.f sold
------------------------------
(1) +a+%2B+b+=+146+
(2) +7.5a+%2B+7b+=+1065+
------------------------
(2) +75a+%2B+70b+=+10650+
Multiply both sides of (1) by +70+
and subtract (1) from (2)
-------------------------
(2) +75a+%2B+70b+=+10650+
(1) +-70a+-+70b+=+-10220+
----------------------------
+5a+=+430+
+a+=+86+
and
(1) +a+%2B+b+=+146+
(1) +b+=+60+
------------------
86 pounds of c.f. were sold
60 pounds of p.b.f were sold
---------------------------
check:
(2) +7.5%2A86+%2B+7%2A60+=+1065+
(2) +645+%2B+420+=+1065+
(2) +1065+=+1065+
OK

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
total sold 146
total sales 1065
product sold at 7.5 and 7
c+a=146,
7.5*c+7*a=1065
c=146-a
We have two equations with two variables.
We will substitute to make one equation with one variable
7.5*(146-a)+7*a=1065
1095.0-7.5a+7*a=1065
-0.5*a=-30.0
a=60.0
c=146-a
c=86 at $7.50 and a=60 at $7
check
86+60=146
7.5*c+7*a=1065
7.5*86+7*60=1065
645.0+420=1065
1065.0=1065
ok
codetickv