Question 911621: It is a question from 'planes'
Find the equation of plane passing through (2,3,-4), (1,-1,3) & parallel to x-axis.
I tried solving it as given :-
Through (2,3,-4)
A(x-2)+B(y-3)+C(z+4)=0 equation (1)
Through (1,-1,3)
A(1-2)+B(-1-3)+C(-3+4) equation (2)
Since it is parallel to x-axis
A(1)+B(0)+C(0) equation (3)
Eliminating A,B,C by sylvester method
|x-2 y-3 z+4|
|-1 -4 1 |
|1 0 0 |
Please help me solve the question from here on
Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website! There is a problem with the setup.
You can't have a plane that contains those two points and is also parallel to the x-axis.
The vector formed from the two points (1,4,-7) should be perpendicular to the x-axis since the plane is parallel to the x-axis.
However the dot product is not equal to zero.
(1,4,-7)*(1,0,0)=1
Please repost.
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