SOLUTION: I need to know the vertex, axis of symmetry, roots, domain, range for the following problem
Y=2(x-2)^2-2
i also need to know if it opens up or down and if you can graph it that w
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-> SOLUTION: I need to know the vertex, axis of symmetry, roots, domain, range for the following problem
Y=2(x-2)^2-2
i also need to know if it opens up or down and if you can graph it that w
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Question 911618: I need to know the vertex, axis of symmetry, roots, domain, range for the following problem
Y=2(x-2)^2-2
i also need to know if it opens up or down and if you can graph it that would be greatly appreciated. Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! Need to Know: the vertex form of a Parabola opening up(a>0) or down(a<0): where(h,k) is the vertex and x = h is the Line of Symmetry
Y= (x-2)^2-2
Upward a = 2 > 0
V(2,-2), axis of symmetry: x = 2
