SOLUTION: I need steps on how to solve the horizontal and vertical asymptotes of this rational function:
f(x) = 3(2^x)-6
My work so far:
x-int:
3(2^x) = 6
then divide 6/3 = 2
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-> SOLUTION: I need steps on how to solve the horizontal and vertical asymptotes of this rational function:
f(x) = 3(2^x)-6
My work so far:
x-int:
3(2^x) = 6
then divide 6/3 = 2
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Question 911489: I need steps on how to solve the horizontal and vertical asymptotes of this rational function:
f(x) = 3(2^x)-6
My work so far:
x-int:
3(2^x) = 6
then divide 6/3 = 2? is that right?
2^x = 2/2 = 1 so x = (1,0)
y-int:
3(2^0) = 6
3(1)=6
6/3 = 2 so y = (0,2)
Is this right?
I don't know if how to get the horizontal or vertical asymptote please give a step by step of how to get them.
Thank you Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! None. No such vertical asymptote. The function is exponential, not rational. Look for the HORIZONTAL asymptote.
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