SOLUTION: two trains are 5000 ft. apart, heading tower each other, but on separate parallel straight tracks. Train A is traveling at 45 miles per hour and train B is traveling at 24 miles pe
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Question 911461: two trains are 5000 ft. apart, heading tower each other, but on separate parallel straight tracks. Train A is traveling at 45 miles per hour and train B is traveling at 24 miles per hour.
a. change 45 miles per hour and 24 miles per hour into feet per second
66ft per second and 35.2 ft per second
b. About how far will each train travel before they meet?
***Please help with the equation I need to use.
c. In how may seconds will Train A and Train B meet?
***Please help with the equation I need to use.
Thank you. Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! I changed to miles
5000/5280 miles
(45+24)*t=5000/5280
69t=(5000/5280)
t=(5000/5280)/69
0.01372419850680720245937637241985 hours
0.82345191040843214756258234519104 minutes
49.407114624505928853754940711462 seconds
0.01372419850680720245937637241985*45=0.61758893280632411067193675889325 miles
=3260.8695652173913043478260869564 feet
0.01372419850680720245937637241985*24=0.3293807641633728590250329380764 miles
=1739.1304347826086956521739130434 feet
