SOLUTION: At noon a train leaves cleveland and heads due north at 10 mph. Another train leaves at 1pm going due east at 20 mph. how fast is the distance between them changing at 3pm?

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Question 911344: At noon a train leaves cleveland and heads due north at 10 mph. Another train leaves at 1pm going due east at 20 mph. how fast is the distance between them changing at 3pm?

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Hey wait, trains don't leave north out of Cleveland, they'd end up in Lake Erie.
But anyways.
Find the distance between them,
At 1pm, the first train is already 10 miles north and it's distance is,
D%5B1%5D=10%2B10t, where t starts counting at 1pm.
The second train's distance is,
D%5B2%5D=20t eastbound.
The two distances form the legs of a right triangle.
To calculate the distance between them find the hypotenuse.
D%5E2=D%5B1%5D%5E2%2BD%7B2%5D%5E2
D%5E2=%2810%2B10t%29%5E2%2B%2820t%29%5E2
To find the rate of change of D, take the derivative with respect to t.
2D%28dD%2Fdt%29=2%2810%2B10t%29%2810%29%2B2%2820t%29%2820%29
2D%28dD%2Fdt%29=200%2B200t%2B800t
2D%28dD%2Fdt%29=1000t%2B200
So at 3pm, t=2
D%5E2=%2810%2B10%282%29%29%5E2%2B%2820%282%29%29%5E2
D%5E2=%2830%292%2B%2840%29%5E2
D%5E2=%2850%29%5E2
D=50
So then,
2%2850%29%28dD%2Fdt%29=1000%282%29%2B200
100%28dD%2Fdt%29=2200
dD%2Fdt=22miles%2Fhr