SOLUTION: PLEASE HELP ME PLEASE. Trical is ten times older than his son, Algeom. In 20 years, Trical's age will be 4 more than twice Algeom's age. How old was he when Algeom was born?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: PLEASE HELP ME PLEASE. Trical is ten times older than his son, Algeom. In 20 years, Trical's age will be 4 more than twice Algeom's age. How old was he when Algeom was born?      Log On

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Question 911303: PLEASE HELP ME PLEASE.
Trical is ten times older than his son, Algeom. In 20 years, Trical's age will be 4 more than twice Algeom's age. How old was he when Algeom was born?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
One key thing to keep in mind is
that the difference in their ages never changes
--------------------
Let +s+ = son's age now
Let +f+ = father's age now
+s+%2B+20+ = son's age in 20 years
+f+%2B+20+ = father's age in 20 years
--------------------------
(1) +f+=+10s+
(2) +f+%2B+20+=+2%2A%28+s+%2B+20+%29+%2B+4+
------------------------------
Substitute (1) into (2)
(2) +10s+%2B+20+=+2%2A%28+s+%2B+20+%29+%2B+4+
(2) +10s+%2B+20+=+2s+%2B+40+%2B+4+
(2) +8s+=+24+
(2) +s+=+3+
and
(1) +f+=+10s+
(1) +f+=+10%2A3+
(1) +f+=+30+
The difference in their ages is
+30+-+3+=+27+ , so
the father was 27 when his son was born
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check:
(2) +10s+%2B+20+=+2%2A%28+s+%2B+20+%29+%2B+4+
(2) +10%2A3+%2B+20+=+2%2A%28+3+%2B+20+%29+%2B+4+
(2) +30+%2B+20+=+2%2A23+%2B+4+
(2) +50+=+46+%2B+4+
(2) +50+=+50+
OK