SOLUTION: Twice the first of three consecutive even integers minus the third equals 36. Find the three integers.

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Question 911278: Twice the first of three consecutive even integers minus the third equals 36. Find the three integers.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Previously Posted
three consecutive integers: x, x+1, x+2
2x - (x+2) = 36
2x - x = 38
x = 38
The three consecutive integers are: 38,39,40
And...checking
76 - 40 = 36