SOLUTION: for what value(s) will the constant k will the following function NOT be it's own inverse? f(x)=(x-k)/(x-1)

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Question 911269: for what value(s) will the constant k will the following function NOT be it's own inverse?
f(x)=(x-k)/(x-1)

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Attempting just to find a formula for the inverse, f%5E-1%28x%29=%28x-k%29%2F%28x-1%29 as expected.

Look at the function definition.
x<>1 because f is undefined there.
x=0 makes for f=k, a constant.
x=k makes f=0.
We want to know a certain value for k so that f has either a different inverse or has no inverse.

k=0, f is just a more specific function.
k=1, then f%28k%29=f%281%29=1, which is a constant.

For highlight%28k=1%29, f will be the line f%28x%29=1, a HORIZONTAL LINE, the same "y" for all values of x. If you reflect this over the line y=x, this forms the inverse RELATION, x=1. This is NOT a function; because it is a VERTICAL LINE, and has infinite values of y for just one value of x.

For what value(s) will the constant k will the following function NOT be it's own inverse?

ANSWER: highlight%28k=1%29.