SOLUTION: Joan ran from her home to the lake at 2mph faster than she ran from the lake back home. If she took 0.25 of an hour to run to the lake and 0.32 of an hour to run back home, how fas

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Joan ran from her home to the lake at 2mph faster than she ran from the lake back home. If she took 0.25 of an hour to run to the lake and 0.32 of an hour to run back home, how fas      Log On

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Question 911003: Joan ran from her home to the lake at 2mph faster than she ran from the lake back home. If she took 0.25 of an hour to run to the lake and 0.32 of an hour to run back home, how fast did she run in each direction?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Joan ran from her home to the lake at 2mph faster than she ran from the lake back home. If she took 0.25 of an hour to run to the lake and 0.32 of an hour to run back home, how fast did she run in each direction?
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let x=speed from the lake to back home
x+2=speed to the lake
distance=travel time*speed
..
.25(x+2)=.32x
.25x+.5=.32x
.07x=.50
x=.50/.07
x=7.14
x+2=9.14
speed from the lake=7.14 mph
speed to the lake=9.14 mph