Question 910967: Rectangle form for r^2 =-csc theta
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Rectangle form for r^2 =-csc theta
-
r^2 = x^2+y^2
theta = arctan(y/x)
------
So, -csc(theta) = -r/y = -sqrt(x^2+y^2)/y
------------------------
Substitute into the given equation to get:
x^2 + y^2 = -sqrt(x^2+y^2)/y
----------------------------------
y = -sqrt(x^2+y^2)/(x^2+y^2)
----
y = -1/sqrt(x^2+y^2)
=============================
Cheers,
Stan H.
-----------------
|
|
|
