Question 910899: Q: A mason wants to be sure he has a right angle corner of a building's foundation. He marks a point 6 feet from the corner along one wall and another point 8 feet from the corner along the other wall. If the corner is a right angle, what should the distance be between the two marked points?
I know you draw a triangle, on the slope right-hand side of it (hypotenuse)is X, on the bottom is 8ft and on the left-hand side is 6ft. I've been trying to figure this out for over an hour and go blank. I know a formula you can use is a^2+b^2=c^2. PLEASE help and solve this in FULL, with step to step solving and answer!
Answer by richwmiller(17219)   (Show Source):
You can put this solution on YOUR website! a^2+b^2=c^2
6^2+8^2=c^2
36+64=c^2
What are we trying to show?
We want to know if the angle formed by the two sides of the triangle is a right angle.
What should c be if it is a right angle?
If the corner is a right angle, what should the distance be between the two marked points?
Why can't the answer be c^2=100
What does it mean if c=10?
Why do you think we were using a^2+b^2=c^2
We knew a and b but we didn't know c. Now we do.
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