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Question 910816: Write an equation of the line passing through (4,-2) and perpendicular to x= 5/4 y - 2
Answer by LinnW(1048)   (Show Source):
You can put this solution on YOUR website! x= 5/4 y - 2
First change the form of the original equation by solving for y
add 2 to each side
x + 2 = 5/4y
reorder
5/4y = x + 2
multiply each side by 4/5
y = 4/5x + 2(4/5)
The slope of the original equation is 4/5,
so the slope of a line perpendicular is -5/4.
Now we want to use the template y = mx + b and the point (4,-2)
We have m = -5/4 , x = 4 and y = -2 so y = mx + b becomes
-2 =(-5/4)(4) + b
-2 = (-20/4) + b
-2 = -5 + b
add 5 to each side
3 = b
Our equation thru point (4,-2) is y = (-5/4)x + 3
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