SOLUTION: trying to solve y to the fourth power over y to the eleventh power. How do I solve this?

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Question 910595: trying to solve y to the fourth power over y to the eleventh power. How do I solve this?

Found 2 solutions by jim_thompson5910, josmiceli:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The bases are the same (both are y). When you divide expressions like this, you subtract the exponents

So,

%28y%5E4%29%2F%28y%5E%2811%29%29+=+y%5E%284-11%29+=+y%5E%28-7%29

Most books want the exponent to be positive, so flip the fraction (y = y/1) to get 1/y with a positive exponent of 7.

So y%5E%28-7%29+=+1%2F%28y%5E7%29

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Therefore, %28y%5E4%29%2F%28y%5E%2811%29%29+=+1%2F%28y%5E7%29

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Use the rule:
+1%2Fa%5Eb+=+a%5E%28-b%29+
+1%2Fy%5E11+=+y%5E%28-11%29+
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Now the expression looks like:
+y%5E4+%2A+y%5E%28-11%29+
Now use the rule:
+a%5Eb+%2A+a%2Ac+=+a%5E%28+b%2Bc+%29+
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+y%5E4+%2A+y%5E%28-11%29+=+y%5E%28+4+-+11+%29+
+y%5E%28+4+-+11+%29+=+y%5E%28-7%29+