SOLUTION: I need to know the Vertex, Axis of Symmetry, roots, domain, and the range for the following problem. Y=x^2-4 I also need to know if it opens up or down and if you could graph it

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I need to know the Vertex, Axis of Symmetry, roots, domain, and the range for the following problem. Y=x^2-4 I also need to know if it opens up or down and if you could graph it       Log On


   



Question 910369: I need to know the Vertex, Axis of Symmetry, roots, domain, and the range for the following problem.
Y=x^2-4
I also need to know if it opens up or down and if you could graph it that would be greatly appreciated.

Found 2 solutions by richwmiller, ewatrrr:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
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Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
recommend the free graphing software download:
https://www.padowan.dk/download/
Algebraically
y = x^2 - 4 = = (x+2)(x-2) roots: -2,2
........
the vertex form of a Parabola opening up(a>0) or down(a<0), y=a%28x-h%29%5E2+%2Bk
where(h,k) is the vertex and x = h is the Line of Symmetry
.......
y = x^2 - 4 V(0,-4), Axis of Symmetry x = 0, a= 1> 0 Opens Upward
domain: All real Numbers
range [-4, ∞ )