SOLUTION: Find three consecutive integers such that the sum of twice the smallest and 3 times the largest is 126

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Question 910233: Find three consecutive integers such that the sum of twice the smallest and 3 times the largest is 126
Answer by Lenzky(18) About Me  (Show Source):
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Let x be the smallest number
x+1 be the second
x+2 be the largest
2x + 3(x+2) = 126
2x+3x+6=126
2x+3x=126-6
5x=120
x=24
x+1=?
24+1=25
x+2=?
24+2=26
Checking:
2(24)+3(26)=126
48+78=126
126=126