SOLUTION: (2x+3)(x+1)-3(x+2)(x+1)=-3(x+5) I keep getting: -x^2-x+9=0 but that isnt factorable.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: (2x+3)(x+1)-3(x+2)(x+1)=-3(x+5) I keep getting: -x^2-x+9=0 but that isnt factorable.      Log On


   

Question 910055: (2x+3)(x+1)-3(x+2)(x+1)=-3(x+5)

I keep getting: -x^2-x+9=0 but that isnt factorable.
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
%282x%2B3%29%28x%2B1%29-3%28x%2B2%29%28x%2B1%29=-3%28x%2B5%29
2x%5E2%2B5x%2B3-3%28x%5E2%2B3x%2B2%29=-3x-15
2x%5E2%2B5x%2B3-3x%5E2-9x-6=-3x-15
-x%5E2-4x-3=-3x-15
-x%5E2-x-3%2B15=0
-x%5E2-x%2B12=0
-1%28-x%5E2-x%2B12%29=0%28-1%29
highlight_green%28x%5E2%2Bx-12=0%29, which is factorable