Question 909856: the sum of the square of two number is 39, the first number being one less their twice the second number. determine the numbers. Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! (2x-1)^2 + x^2 = 39
4x^2 - 4x + 1 + x^2 = 39
5x^2 - 4x - 38 = 0
x = 3.18567765543682, -2.38567765543682
find corresponding values for (2x-1)to determine the number pairs.