SOLUTION: the length of a rectangle is 12 ft longer than twice the width. If the perimeter is 102 ft. find the length and width of the rectangle
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Question 909751: the length of a rectangle is 12 ft longer than twice the width. If the perimeter is 102 ft. find the length and width of the rectangle
You can put this solution on YOUR website! P = 2L + 2W
P = 102
L = 2W+12
102 = 2(2W+12) + 2W
102 = 4W + 24 + 2W
102 = 6W + 24
78 = 6W
13 = W
If the width is 13, then the length is twice that plus 12, or 38
38 + 38 + 13 + 13 = 102