SOLUTION: the length of the base of an isosceles triangle is one forth the length of one of its legs if the perimeter of the triangle is 16 inches, what is the length of the base?

Algebra ->  Triangles -> SOLUTION: the length of the base of an isosceles triangle is one forth the length of one of its legs if the perimeter of the triangle is 16 inches, what is the length of the base?      Log On


   

Question 909609: the length of the base of an isosceles triangle is one forth the length of one of its legs if the perimeter of the triangle is 16 inches, what is the length of the base?
Answer by JulietG(1812) About Me  (Show Source):
You can put this solution on YOUR website!
An isosceles triangle has two legs of equal length.
The perimeter is 16", which is the base + both legs.
The base = 1/4x the length
L = 4B
B + 2L = 16
B +2(4B) = 16
9B = 16
B = 16%2F9
If the base is 16%2F9, then the lengths are 64%2F9
16%2F9+64%2F9+64%2F9= 144%2F9 or 16