SOLUTION: one number is five more than another. if twice the smaller is decreased by 4 the result is eighteen more than the larger. find the number.

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Question 909551: one number is five more than another. if twice the smaller is decreased by 4 the result is eighteen more than the larger. find the number.
Answer by JulietG(1812) About Me  (Show Source):
You can put this solution on YOUR website!
A = B + 5
2B-4 = A+18
Substitute the known value of A from the first equation into the second.
2B-4 = A+18
2B-4 = (B+5)+18
2B-4 = B+23
Subtract B from each side and add 4 to each side
B = 27
If B is 27, then A is 32


Twice 27 less 4 = 50, which is 18 more than 32.