SOLUTION: Allen is three times as old as Betty, and Luz is five years younger than Allen. Three years ago, the sum of their ages was 56 years. What are their present ages?
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Question 909175: Allen is three times as old as Betty, and Luz is five years younger than Allen. Three years ago, the sum of their ages was 56 years. What are their present ages?
Show a solution. Answer by JulietG(1812) (Show Source):
You can put this solution on YOUR website! If 3 years ago, the sum was 56, then their present sum is 56+3+3+3 = 65.
A + B + L = 65
B = A
L = A-5
Take the known values from the bottom equation and put them into the top
A + B + L = 65
A +A + (A-5) = 65
2A - 5 = 65
2A = 70
Divide each side by 2
A = 30
If Allen is 30, then Betty is 10, and Luz is 25
