SOLUTION: A distributor has two gasohol blends: one that contains 5.00% alcohol and another with 11.0% alcohol. How many litres of each must be mixed to make 588 L of gasohol containing 9.50

Click here to see ALL problems on Proportions

Question 909139: A distributor has two gasohol blends: one that contains 5.00% alcohol and another with 11.0% alcohol. How many litres of each must be mixed to make 588 L of gasohol containing 9.50% alcohol?

Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website!
By addition/elimination
We know the total amount is 588 liters
We know the percentage of the total amount is 9.5%
We know the total amount has 55.86 liters of 100%
We want to know the amount of solution at 5%
We want to know the amount of solution at 11%
1*x+1*y=588,
0.05*x+0.11*y=0.095*588
0.05*x+0.11*y=55.86
multiply by 1/0.05
z=20
x+2.2*y=1117.2
1*x+1*y=588,
subtract
1.2y=1117.2-588
1.2y=529.2
y=529.2/1.2
y=441.0
We now know amount of solution at 11%
y=441.0 liters at 11%
x=588-y
We now know amount of solution at 5%
x=147.0 liters at 5%
check
0.05*147.0+0.11*441.0=0.095*588
7.35+48.51=55.86
55.86=55.86
ok