SOLUTION: sinx= 4/5 x is in quadrant II cosx= tanx= cotx= secx= cscx=

Algebra ->  Trigonometry-basics -> SOLUTION: sinx= 4/5 x is in quadrant II cosx= tanx= cotx= secx= cscx=      Log On


   



Question 909114: sinx= 4/5 x is in quadrant II
cosx=
tanx=
cotx=
secx=
cscx=

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
in quadrant 1, the sine is equal to opposite divided by hypotenuse.

opposite side is 4
hypotenuse is 5
adjacent side is 3 because this is a 3/4/5 triangle.

in quadrant 2, the opposite side and the hypotenuse are positive, but the adjacent side is negative.

this is because opposite side is y and y is positive in quadrant 2.
this is because hypotenuse is always positive.
this is because adjacent side is x and x is negative in quadrant 2.

the sides in quadrant 2 are therefore:

opposite side is 4
hypotenuse is 5
adjacent side is -3.

now you can find all your trig functions.

sine is 4/5
cosine is -3/5
tangent is -4/3
cotangent is -3/4
secant is -5/3
cosecant is 5/4

cotangent is equal to 1/tangent

secant is equal to 1/cosine

cosecant is equal to 1/sine