Question 909108: Ten years ago, father was 12 times as old as his son and ten years hence,he will be twice as old as his son.Find their present age. Answer by clearblueskai(22) (Show Source):
You can put this solution on YOUR website! Ten years ago, father was 12 times as old as his son and ten years hence,he will be twice as old as his son.Find their present age.
x= father's present age
y= son's present age
10 years ago:
10 years from now:
Ten years ago, father was 12 times as old as his son:
Ten years hence, he will be twice as old as his son:
System of equations:
Eliminate one variable + =
Plug in the value of y to any of the equations:
