SOLUTION: {{{16(3a+m)^2 -25x^2 +100xy -100y^2}}} How would I factor this? My attempt: {{{16(3a+m)^2 - (5x-10y)^2}}} {{{(4(3a+M)+5x-10y)(4(3a+M)-5x-10y)}}} {{{(12a+4m+5x-10y)(12a+4

Algebra ->  Expressions-with-variables -> SOLUTION: {{{16(3a+m)^2 -25x^2 +100xy -100y^2}}} How would I factor this? My attempt: {{{16(3a+m)^2 - (5x-10y)^2}}} {{{(4(3a+M)+5x-10y)(4(3a+M)-5x-10y)}}} {{{(12a+4m+5x-10y)(12a+4      Log On


   

Question 909081: 16%283a%2Bm%29%5E2+-25x%5E2+%2B100xy+-100y%5E2
How would I factor this?
My attempt:
16%283a%2Bm%29%5E2+-+%285x-10y%29%5E2
%284%283a%2BM%29%2B5x-10y%29%284%283a%2BM%29-5x-10y%29
%2812a%2B4m%2B5x-10y%29%2812a%2B4m-5x-10y%29
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You made an error. When you went from 16%283a%2Bm%29%5E2+-+%285x-10y%29%5E2 to %284%283a%2Bm%29%2B5x-10y%29%284%283a%2Bm%29-5x-10y%29 you made a mistake.

It *should* be this

16%283a%2Bm%29%5E2+-+%285x-10y%29%5E2

%284%283a%2Bm%29+%2B+%285x-10y%29%29%284%283a%2Bm%29+-+%285x-10y%29%29

%284%283a%2Bm%29+%2B+5x-10y%29%284%283a%2Bm%29+-+5x%2B10y%29

notice on the last line I have -5x+10y (whereas you have -5x-10y). So it was a case of you not distributing the negative through fully.

I'll let you finish up.