SOLUTION: suppose two trains leave a station at the same time, traveling in opposite directions. One train travels 20 mph faster than the other. In 3.5 hours they are 371 miles apart. Find t
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Question 909061: suppose two trains leave a station at the same time, traveling in opposite directions. One train travels 20 mph faster than the other. In 3.5 hours they are 371 miles apart. Find the speed of each train Found 3 solutions by JulietG, richwmiller, josmiceli:Answer by JulietG(1812) (Show Source):
You can put this solution on YOUR website! X + (x+20) =
2X + 20 = 106
2X = 86
X = 43
The slower train is traveling 43 mph
The faster train is traveling 63 mph
They travel apart 106 miles each hour
106 * 3.5 = 371
You can put this solution on YOUR website!
3.5*x+3.5*(x+20)=371
3.5*x+3.5*x+3.5*20=371
7.0*x+70.0=371
7.0*x=371-70.0
7.0*x=301.0
x=301.0/7.0
x=43.0
x+20=63
or
3.5*(x+x+20)=371
3.5*(2x+20)=371
3.5*2x+3.5*20)=371
7.0x+3.5*20=371
7.0x+70.0=371
7.0*x=371-70.0
7.0*x=301.0
x=301.0/7.0
x=43.0
check
x+20=63
You can put this solution on YOUR website! You can think of this as one train
standing still and the other moving
at the sum of their speeds.
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Let = the speed of the slower train = the speed of the faster train
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The slower train's speed is 43 mi/hr
The faster train's speed is 63 mi/hr
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check:
Slower train:
Faster train:
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OK
