SOLUTION: What is the lowest cost? 40x+10y>=2600 10X+15y>=2100 5x+12y>=1500 ×>=0, y>=0

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Question 909047: What is the lowest cost?
40x+10y>=2600
10X+15y>=2100
5x+12y>=1500
×>=0, y>=0
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
You forgot to give the Cost function, so I made one up,

C = 700x + 500y

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Minimize the cost function

C = 700x + 500y 

subject to these constraints:



Draw the boudary lines, determine the feasible region,
and find the intersections of the corner points of the
feasible region: 

  

So we see that the cost is lowest at $83,200 when x=36 and y=116.

Edwin